Chapter 10 - Systems of Equations and Inequalities - Section 10.6 Systems of Nonlinear Equations - 10.6 Assess Your Understanding - Page 794: 14

See graphs, $(2,-2),(-2,-2)$

1. See graphs for $x^2+y^2=8$ and $x^2+y^2+4y=0$ 2. Take the difference of the two equations to get $4y=-8$, thus $y=-2$ 3. Use the 1st equation with $y=-2$, we can find the intersect(s) $(2,-2),(-2,-2)$