Chapter 10 - Systems of Equations and Inequalities - Section 10.6 Systems of Nonlinear Equations - 10.6 Assess Your Understanding - Page 794: 37

$(\sqrt 2, 2\sqrt 2),(-\sqrt 2, -2\sqrt 2)$

1. Multiply 2 to the 2nd equation and add to the 1st, we have $7x^2=14$, thus $x=\pm\sqrt 2$ 2. Multiply -3 to the 1st equation and add to the 2nd, we have $-7xy=-28$, thus $y=\frac{4}{x}=\pm2\sqrt 2$ 3. The solutions $(\sqrt 2, 2\sqrt 2),(-\sqrt 2, -2\sqrt 2)$