Answer
no real solution.
Work Step by Step
Multiply 2 to the 1st equation and add to the 2nd, we have $5x^2+8=4$, thus $x^2=-\frac{4}{5}$, as a square can not be negative, there is no real solution.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 10 - Systems of Equations and Inequalities - Section 10.6 Systems of Nonlinear Equations - 10.6 Assess Your Understanding - Page 794: 39
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