Answer
See graphs, $(0,2),\left(0,-2\right),\left(-1,-\sqrt{3}\right), \left(-1,\sqrt{3}\right)$
Work Step by Step
1. See graphs for $x^2+y^2=4$ and $y^2-x=4$
2. Take the difference of the two equations to get $x^2+x=0$, thus $x=-1, 0$
3. Use the above results with the 2nd equation, we can find the intersect(s) $(0,2),\left(0,-2\right),\left(-1,-\sqrt{3}\right),\left(-1,\sqrt{3}\right)$
