Answer
$(-5,-\frac{3}{2})$
Work Step by Step
1. From the 2nd equation, we have $x=2y-2$
2. Use the above in the 1st equation to get $(2y-2)^2-4y^2=16$ or $(y-1)^2-y^2=4$ or $-2y+1=4$, thus $y=-\frac{3}{2}$
3. Use the 2nd equation to get $x=2(-\frac{3}{2})-2=-5$
4. Thus the solution $(-5,-\frac{3}{2})$