Answer
$(0,-1),(\frac{5}{2},-\frac{7}{2})$
Work Step by Step
1. From the 1st equation, we have $x=-y-1$
2. Use the above in the 2nd equation to get $(-y-1)^2+y^2+6y-(-y-1)=-5$ or $2y^2+9y+7=0$, thus $(y+1)(2y+7)=0, y=-1,-\frac{7}{2}$
3. Use the 1st equation with the above results to get $x=0,\frac{5}{2}$
4. Thus the solution $(0,-1),(\frac{5}{2},-\frac{7}{2})$
