Chapter 10 - Systems of Equations and Inequalities - Section 10.6 Systems of Nonlinear Equations - 10.6 Assess Your Understanding - Page 794: 10

See graphs, $(4,2)$

1. See graphs 2. Use $y=\sqrt {x}$ in $y=6-x$ to get $\sqrt x=6-x$ or $x+\sqrt x-6=0$ 3. Factor to get $(\sqrt x+3)(\sqrt x-2)=0$, thus $\sqrt x=2$ (discard the negative answer) and $x=4$ 4. Use the 2nd equation again to get $y=2$ 5. We can find the intersect(s) $(4,2)$