Chapter 10 - Systems of Equations and Inequalities - Section 10.6 Systems of Nonlinear Equations - 10.6 Assess Your Understanding - Page 794: 22

See graphs, $\left(\frac{1}{2},2\right),\left(-1,-1\right)$

1. See graphs for $xy=1$ and $y=2x+1$ 2. Plug the 2nd equation in the 1st to get $x(2x+1)=1$ or $2x^2+x-1=0$ or $(x+1)(2x-1)=0$, thus $x=-1, \frac{1}{2}$ 3. Use the 2nd equation with the above, we can find the intersect(s): $\left(\frac{1}{2},2\right),\left(-1,-1\right)$