Chapter 10 - Systems of Equations and Inequalities - Section 10.6 Systems of Nonlinear Equations - 10.6 Assess Your Understanding - Page 794: 5

See graphs, $(0,1),(1,2)$

1. See graphs for $y=x^2+1$ and $y=x+1$ 2. From the two equations, we have $x^2+1=x+1$ or $x^2-x=0$, thus $x=0,1$ 3. Use the 2nd equation with $x=0,1$, we can find the intersect(s) $(0,1),(1,2)$