Chapter 10 - Systems of Equations and Inequalities - Section 10.6 Systems of Nonlinear Equations - 10.6 Assess Your Understanding - Page 794: 16

See graphs, $(-3,-1),\left(1,3\right)$

1. See graphs for $y=x+2$ and $x^2+y^2=10$ 2. Use the 1st equation in the 2nd to get $x^2+x^2+4x+4=10$ or $x^2+2x-3=0$ or $(x+3)(x-1)=0$, thus $x=-3, 1$ 3. Use the above results with the 1st equation, we can find the intersect(s) $(-3,-1),\left(1,3\right)$