Answer
See graphs, $(1,1)$
Work Step by Step
1. See graphs for $x^2=y$ and $xy=1$
2. Use the 1st equation in the 2nd to get $x(x^2)=1$ or $x^3=1$, thus $x=1$
3. Use the 1st equation with $x=1$, we can find the intersect(s): $(1,1)$
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