Answer
See graphs, $(2,1),(5,4)$
Work Step by Step
1. See graphs
2. Use $y=x-1$ in $y=x^2-6x+9$ to get $x^2-6x+9=x-1$ or $x^2-7x+10=0$
3. Factor to get $(x-2)(x-5)=0$, thus $x=2, 5$
4. Use the 1st equation again to get $y=1,4$
5. We can find the intersect(s): $(2,1),(5,4)$