Answer
See graphs, $(-2,0)$
Work Step by Step
1. See graphs for $x^2+y^2=4$ and $x^2+2x+y^2=0$
2. Take the difference between the two equations to get $2x=-4$, thus $x=-2$
3. Use the first equation with $x=-2$ to find the intersect(s) $(-2,0)$