Answer
See graph for $y^2=x^2-1$
Work Step by Step
1. For $y^2=x^2-1$ or $x^2-y^2=1$, we can identify that it is a hyperbola centered at $(0,0)$ with a horizontal major axis and $a=b=1$.
2. With the above results and known the asymptotes $y=\pm x$ and vertices $(1,0),(-1,0)$, we can graph the equation.