Answer
See graphs, $(1,-2),(2,1)$
Work Step by Step
1. See graphs for $y=3x-5$ and $x^2+y^2=5$
2. Use the 1st equation in the 2nd to get $x^2+9x^2-30x+25=5$ or $10x^2-30x+20=0$ or $x^2-3x+2=0$ or $(x-1)(x-2)=0$, thus $x=1, 2$
3. Use the above results with the 1st equation, we can find the intersect(s) $(1,-2),(2,1)$