Answer
See graph for $y+4=x^2$
Work Step by Step
1. For $y+4=x^2$ or $y=x^2-4$, we can identify that it is a parabola with vertex at $(0,-4)$, and opens upward.
2. With a symmetry axis $x=0$ and a few test points $(1,-3),(2,0),(3,5)$, we can graph the equation.