Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 47



Work Step by Step

$\frac{dy}{dx}=x^3;$ $y(0)=4$ $dy=x^3dx$ $\int dy=\int x^3dx$ $y=\frac{x^4}{4}+C$ Substitute in initial condition $4=0+C$ $C=4$ $y=\frac{x^4}{4}+4$
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