Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 24


$\int\frac{12-z}{\sqrt z}dz =24z^\frac{1}{2}-\frac{2}{3}z^\frac{3}{2} +C $

Work Step by Step

$\int\frac{12-z}{\sqrt z}dz = \int12z^{-\frac{1}{2}} - z^{\frac{1}{2}} dz = 12\times\frac{1}{\frac{1}{2}}z^\frac{1}{2}- \frac{1}{\frac{3}{2}}z^\frac{3}{2} +C = 24z^\frac{1}{2}-\frac{2}{3}z^\frac{3}{2} +C $
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