Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 7


$\int 12e^x- 5x^{-2} dx= 12e^x +5x^{-1} + C$

Work Step by Step

Rules to remember: $\int e^xdx = e^x + C $ Anti-differentiation: $\int 12e^x- 5x^{-2} dx= 12e^x - 5\times\frac{1}{-1} x^{-1} + C= 12e^x + 5x^{-1}+C$ Checking with differentiation: $(12e^x + 5x^{-1}+C)'= 12e^x - \frac{5}{x^2}$
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