## Calculus (3rd Edition)

$F(x)$ is the antiderivative of $f(x)$.
We have $$\frac{1}{7}((x+13)^7+c)'=\frac{7}{7}(x+13)^6=((x+13)^6$$ that is, $\int(x+13)^{6} d x=\frac{1}{7}(x+13)^{7}+C$.