Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 16


$\int14s^{\frac{9}{5}}ds = 5s^{\frac{15}{4}}+C$

Work Step by Step

$\int14s^{\frac{9}{5}}ds = 14\times\frac{1}{\frac{14}{5}}s^\frac{14}{5}+C = 14\times\frac{5}{14}s^{\frac{15}{4}} +C= 5s^{\frac{15}{4}}+C$
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