Answer
$\int14s^{\frac{9}{5}}ds = 5s^{\frac{15}{4}}+C$
Work Step by Step
$\int14s^{\frac{9}{5}}ds = 14\times\frac{1}{\frac{14}{5}}s^\frac{14}{5}+C = 14\times\frac{5}{14}s^{\frac{15}{4}} +C= 5s^{\frac{15}{4}}+C$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 16
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