Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 21


$\int\frac{36dt}{t^3}= -18t^{-2} +C$

Work Step by Step

$\int\frac{36dt}{t^3}= 36 \int t^{-3} dt = 36\times\frac{1}{-2}t^{-2} +C= -18t^{-2} +C$
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