Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises: 21

Answer

$\int\frac{36dt}{t^3}= -18t^{-2} +C$

Work Step by Step

$\int\frac{36dt}{t^3}= 36 \int t^{-3} dt = 36\times\frac{1}{-2}t^{-2} +C= -18t^{-2} +C$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.