Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 26


$\int(\frac{1}{3}sin(x)-\frac{1}{4}cos(x)) dx= -\frac{1}{3}cos(x) -\frac{1}{4}sin(x) +C $

Work Step by Step

Rules to remember: $sin(x)' = cos(x)$, $cos(x)' = -sin(x)$ $\int(\frac{1}{3}sin(x)-\frac{1}{4}cos(x)) dx= -\frac{1}{3}cos(x) -\frac{1}{4}sin(x) +C $
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