Answer
$\int sin(7x)dx=-\frac {cos(7x)}{7}+C$
Work Step by Step
$\int sin(7x)dx$
$=\frac{1}{7}\int 7sin(7x)dx;$ $u=7x;$ $du=7dx$
$=\frac{1}{7}\int sin(u)du$
$=\frac{1}{7}(-cos(u))+C$
$=-\frac {cos(7x)}{7}+C$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 30
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