Answer
$\int\frac{1}{\sqrt[3] x}dx=\frac{3}{2}x^\frac{2}{3}+C$
Work Step by Step
$\int\frac{1}{\sqrt[3] x}dx= \int x^{-\frac{1}{3}}dx= \frac{1}{\frac{2}{3}}x^{\frac{2}{3}}+C= \frac{3}{2}x^\frac{2}{3}+C$
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