Answer
$F(x)$ is the antiderivative of $f(x)$.
Work Step by Step
We have
$$ (\frac{1}{a(n+1)}(a x+b)^{n+1}+C)'=\frac{n+1}{a(n+1)}(a x+b)^{n}(a)=(a x+b)^{n}$$
that is, $\int(a x+b)^{n} d x=\frac{1}{a(n+1)}(a x+b)^{n+1}+C$.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 46
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