Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 35


$$\frac{1}{12} \sec(12t)+c$$

Work Step by Step

Since $(\sec(12t ))'=12 \sec(12t )\tan(12t )$, we have $$\int \sec(12t )\tan(12t ) dt=\frac{1}{12}\int 12\sec(12t )\tan(12t ) dt \\ =\frac{1}{12} \sec(12t)+c.$$
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