Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 12


$\int x^{-3} dx = -\frac{1}{2x^2}+C$

Work Step by Step

$\int x^{-3} dx = \frac{1}{-2}x^{-2} +C= -\frac{1}{2x^2}+C$
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