Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises: 12

Answer

$\int x^{-3} dx = -\frac{1}{2x^2}+C$

Work Step by Step

$\int x^{-3} dx = \frac{1}{-2}x^{-2} +C= -\frac{1}{2x^2}+C$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.