Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 36


$$\frac{5}{4}\sin(4\theta +3)+c.$$

Work Step by Step

Since $(\sin(4\theta +3))'=4\cos(4\theta +3)$, we have $$\int 5\cos(4\theta +3) d\theta=\frac{5}{4}\int 4\cos(4\theta +3) d\theta \\ =\frac{5}{4}\sin(4\theta +3)+c.$$
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