Answer
$$\frac{5}{4}\sin(4\theta +3)+c.$$
Work Step by Step
Since $(\sin(4\theta +3))'=4\cos(4\theta +3)$, we have
$$\int 5\cos(4\theta +3) d\theta=\frac{5}{4}\int 4\cos(4\theta +3) d\theta \\
=\frac{5}{4}\sin(4\theta +3)+c.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 36
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