Answer
$\int x(x^2-4)dx = \frac{1}{4}x^4 -2x^2+C$
Work Step by Step
$\int x(x^2-4)dx = \int(x^3-4x)dx = \frac{1}{4}x^4 -4\times\frac{1}{2}x^2 +C = \frac{1}{4}x^4 -2x^2+C$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 22
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