Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 1


$\int18x^2= 6x^3 + C$

Work Step by Step

Anti-differentiation: $\int18x^2= 18\int x^2= 18\times\frac{1}{1+2} x^3 + C= 18\times\frac{1}{3}x^3 + C =6x^3 +C $ Checking with differentiation: $(6x^3+ C)' = 6\times3 x^2 = 18x^2 $
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