Answer
$F(x)$ is the antiderivative of $f(x)$.
Work Step by Step
We have
$$ (\frac{1}{12}(4x+13)^{3}+C)'=\frac{3}{12}(4x+13)^{2}(4)=(x+13)^{2}$$
that is, $\int(4x+13)^{2} d x= \frac{1}{12}(4x+13)^{3}+C$.
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