Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises: 11

Answer

$\int(4-18x)dx= 4x-9x^2 + C$

Work Step by Step

$\int(4-18x)dx= 4x-18\times\frac{1}{2}x^2 + C= 4x-9x^2 + C$
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