Answer
$\int(4-18x)dx= 4x-9x^2 + C$
Work Step by Step
$\int(4-18x)dx= 4x-18\times\frac{1}{2}x^2 + C= 4x-9x^2 + C$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.3 The Indefinite Integral - Exercises - Page 252: 11
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