Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 352: 8

Answer

$x=0.525$

Work Step by Step

$100e^{-2x}=35$ $e^{-2x}=\frac{7}{20}$ $-2x$ $ln(e)=ln(\frac{7}{20})$ $2x=-ln(\frac{7}{20})$ $x=\frac{-ln(\frac{7}{20})}{2}$ $\approx 0.5249110622$ $=0.525$
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