Answer
$y=-2x+1$
Work Step by Step
$f(x)=e^{-2x}$ $(0,1)$
$fâ(x)=-2e^{-2x}$
$fâ(0)=M=-2e^{-2(0)}$
$M=-2$
Equation of Tangent:
$y-1=-2(x-0)$
$y=-2x+1$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 352: 56
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