Answer
$y’=-6x^2e^{-2x^3}$
Work Step by Step
$y=e^{-2x^3}$
let
u=$-2x^3$
u'=$-6x^2$
$\frac{d}{dx}e^u=u'e^u$
$y’=-6x^2e^{-2x^3}$
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