Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 352: 36

Answer

$y’=-6x^2e^{-2x^3}$

Work Step by Step

$y=e^{-2x^3}$ let u=$-2x^3$ u'=$-6x^2$ $\frac{d}{dx}e^u=u'e^u$ $y’=-6x^2e^{-2x^3}$
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