Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises: 34

Answer

$y’=-8e^{-8x}$

Work Step by Step

$y=e^{-8x}$ let u=-8x u'=-8 $\frac{d}{dx}e^u=e^uu'$ $=e^{-8x}(-8)$ $=-8e^{-8x}$ $y’=-8e^{-8x}$
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