Answer
$y’=-8e^{-8x}$
Work Step by Step
$y=e^{-8x}$
let u=-8x
u'=-8
$\frac{d}{dx}e^u=e^uu'$
$=e^{-8x}(-8)$
$=-8e^{-8x}$
$y’=-8e^{-8x}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 352: 34
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