Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 352: 15

Answer

$x=5.389$

Work Step by Step

$ln(\sqrt{x+2})=1$ $e^{\sqrt{x+2}}=e$ $\sqrt{x+2}=e$ $x+2=e^2$ $x=e^2-2$ $\approx 5.389056099$ $=5.389$
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