Answer
$y’=\frac{1}{2}(e^x+e^{-x})$
Work Step by Step
$y=\frac{1}{2}(e^x-e^{-x})$
let
u=$e^x-e^{-x}$
u'=$e^x+e^{-x}$
$y=\frac{1}{2}u$
$y'=\frac{1}{2}u'$
$y’=\frac{1}{2}(e^x+e^{-x})$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 352: 48
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
