Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises: 17

Answer

See graph
1514151664

Work Step by Step

$e\approx2.718$ is a number greater than one. So the value of $e^{-x} $ will go on decreasing, and the graph is asymptotic to the x-axis grows arbitrarily. For negative values, f $e^{-x} $ grows without bounds as we walk leftwards on the x-axis towards greater and greater negative values. The y-intercept is 1 because $e^{-0} =e^{0}=1 $
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