Answer
See graph
Work Step by Step
$e\approx2.718$ is a number greater than one. So the value of $e^{-x} $ will go on decreasing, and the graph is asymptotic to the x-axis grows arbitrarily.
For negative values, f $e^{-x} $ grows without bounds as we walk leftwards on the x-axis towards greater and greater negative values. The y-intercept is 1 because $e^{-0} =e^{0}=1 $
