Answer
$g’(t)=3(e^{-t}+e^t)^2(-e^{-t}+e^t)$
Work Step by Step
$g(t)=(e^{-t}+e^t)^3$
let
u=$e^{-t}+e^t$
u'=$-e^{-t}+e^t$
$g(u)=u^3$
$g'(u)=3u^2u'$
$g’(t)=3(e^{-t}+e^t)^2(-e^{-t}+e^t)$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 352: 43
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