Answer
$y’=10xe^{x^2+5}$
Work Step by Step
$y=5e^{x^2+5}$
let
u=x^2+5
u'=2x
$\frac{d}{dx}e^u=u'e^u$
$y’=(2x)(5e^{x^2+5})$
$y’=10xe^{x^2+5}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 352: 38
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