Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 352: 38



Work Step by Step

$y=5e^{x^2+5}$ let u=x^2+5 u'=2x $\frac{d}{dx}e^u=u'e^u$ $y’=(2x)(5e^{x^2+5})$ $y’=10xe^{x^2+5}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.