Answer
$y=2x-3$
Work Step by Step
$y=e^{-2x+1}$ $(2,1)$
$y’=(-2+2x)(e^{-2x+x^2})$
$y’(2)=M=(-2+1)(e^{-4+4})$
$=2$
Equation of Tangent:
$y-1=2(x-2)$
$y-1=2x-4$
$y=2x-3$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 352: 58
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