Answer
$y’=(x)(e^{-x})(2-x)$
Work Step by Step
$y=x^2e^{-x}$
$u=x^2$
$u’=2x$
$v=e^{-x}$
$v’=-e^{-x}$
$y’=(2x)(e^{-x})-(x^2)(e^{-x})$
$=(x)(e^{-x})(2-x)$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 352: 42
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