Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises: 63

Answer

$\frac{dy}{dx}=\frac{10-e^y}{3+xe^y}$

Work Step by Step

$xe^y-10x+3y=0$ $(1e^y+xe^y(\frac{dy}{dx}))-10+3\frac{dy}{dx}=0$ $xe^y\frac{dy}{dx}+3\frac{dy}{dx}=10-e^y$ $\frac{dy}{dx}=\frac{10-e^y}{3+xe^y}$
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