Answer
$\frac{dy}{dx}=\frac{10-e^y}{3+xe^y}$
Work Step by Step
$xe^y-10x+3y=0$
$(1e^y+xe^y(\frac{dy}{dx}))-10+3\frac{dy}{dx}=0$
$xe^y\frac{dy}{dx}+3\frac{dy}{dx}=10-e^y$
$\frac{dy}{dx}=\frac{10-e^y}{3+xe^y}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 352: 63
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