Answer
$y'=2e^x(cosx)$
Work Step by Step
$y=e^x(sinx+cosx)$
$u=e^x$
$u’=e^x$
$v=sinx+cosx$
$v’=cos x-sinx$
$y’=e^x(sinx+cosx)+e^x(cosx-sinx)$
$=e^x(2cosx)$
$=2e^x(cosx)$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 352: 51
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