Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 352: 41

Answer

$y’=(e^x)(x^2)(3+x)$

Work Step by Step

$y=x^3e^x$ $u=x^3$ $u’=3x^2$ $v=e^x$ $ v’=e^x$ $y’=(3x^2)(e^x)+(x^3)(e^x)$ $=(e^x)(x^2)(3+x)$
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