Answer
$x=3.912$
Work Step by Step
$\frac{5000}{1+e^{2x}}=2$
$2500=1+e^{2x}$
$2499=e^{2x}$
$ln2499=2x$ $ln(e)$
$x=\frac{ln2499}{2}$
$\approx 3.911822965$
$=3.912$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 352: 10
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