## Calculus 10th Edition

The graph of $e^x+2$ is just the graph of $e^x$ clamped up by two units. So now, instead of being asymptotic to the x-axis(y=0) towards the negative x-axis, the graph is asymptotic to y=2. With positive values, the limits are the same - it approaches infinity as the x approaches infinity. The y-intercept is $y=e^0+2 =1+2 =3$