Answer
$y'=(e^{4x})(1+4x)$
Work Step by Step
$y=xe^{4x}$
$u=x$
$u’=1$
$v=e^{4x}$
$v’=4e^{4x}$
$y’=(1)(e^{$x})+(x)(4e^{4x})$
$=(e^{4x})(1+4x)$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 352: 40
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